The most condensed material in the Universe; 10²⁵ times of a black hole (Cidtonium)

If we want to get the constituent of the Big Bang, we can suggest the photon as the option which based on Saleh Theory is particle. Accordingly the volume and density of the Big Bang will be: mT=1053kgmp=1.67?10?35kgrp =1.2?10?17mn = mTmp=10531.67?10?35?n=6?1087Vp = 43�rp3= 43�(1.2?10?17)3?Vp=7.23?10?51 m3?p=mpVp=1.67?10?357.23?10?51??p=2.31?1015 kgm3VBB=nVp=6?1087?7.23?10?51?VBB=4.33?1037m3VBB=43�rBB3?rBB3=4.33?103743�?rBB=2.18?1012m?BB=mTVBB=10534.33?1037??BB=2.31?1015kgm3 Where mT is the total mass of universe, n is the number of photon, mp,rp,Vp and ?p are the mass, radius, volume and density of the photon and rBB,VBB and ?BB are the radius, volume and density of the Big Bang sphere. Considering that the density of the Big Bang obtained by using photons is about 1015kgm3 and as instant, the radius of the Big Bang sphere will be from the Earth to Jupiter. So, it could not be a suitable choice for the Big Bang, because it does not meet the definition that we expect for the Big Bang. In order to achieve our desired goal, we define a particle whose radius is one billionth of a photon, "Cidtonium". According to this new particle we have: rC =rp?10?9= 1.2?10?26 mVC = 43�rC3= 43�(1.2?10?26)3?VC=7.23?10?78 m3?C=1.67?10?357.23?10?78??C=2.31?1042 kgm3V?BB=nVC=6?1087?7.23?10?78?V?BB=4.33?1010m3V?BB=43�r?BB3?r?BB3=4.33?101043�?r?BB=2.18?103m??BB=mTV?BB=10534.33?1010???BB=2.31?1042kgm3 Where n is the number of Cidtonium, mC,rC,VC and ?C are the mass, radius, volume and density of the Cidtonium and r?BB,V?BB and ??BB are the radius, volume and density of the Big Bang sphere based on Cidtonium. It is clear that the size of the Big Bang sphere based on Cidtonium is about the moon and the density is about 10^42 (kg/m^3) . Therefore, this particle could be a suitable choice for the nature of the Big Bang.